(x-8)(2x^2+7x+4)=0

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Solution for (x-8)(2x^2+7x+4)=0 equation: 


Simplifying
(x + -8)(2x2 + 7x + 4) = 0

Reorder the terms:
(-8 + x)(2x2 + 7x + 4) = 0

Reorder the terms:
(-8 + x)(4 + 7x + 2x2) = 0

Multiply (-8 + x) * (4 + 7x + 2x2)
(-8(4 + 7x + 2x2) + x(4 + 7x + 2x2)) = 0
((4 * -8 + 7x * -8 + 2x2 * -8) + x(4 + 7x + 2x2)) = 0
((-32 + -56x + -16x2) + x(4 + 7x + 2x2)) = 0
(-32 + -56x + -16x2 + (4 * x + 7x * x + 2x2 * x)) = 0
(-32 + -56x + -16x2 + (4x + 7x2 + 2x3)) = 0

Reorder the terms:
(-32 + -56x + 4x + -16x2 + 7x2 + 2x3) = 0

Combine like terms: -56x + 4x = -52x
(-32 + -52x + -16x2 + 7x2 + 2x3) = 0

Combine like terms: -16x2 + 7x2 = -9x2
(-32 + -52x + -9x2 + 2x3) = 0

Solving
-32 + -52x + -9x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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